If the logical memory of 8 X 1024 is mapped into 32 frames, then the number of bits for the logical address are____ ? Click for Solution |
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A log2(8X1024) = log2(8)+log2(1024) = 3+10 = 13
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A there are 8 pages
there are 1024 words per each page
So log 8 =3 bits and log 1024 = 10 bits
LA= 3+10 =13
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A its ans is 13
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A its ans must be 5 bits...1024/32 =32 (2^5)
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A can u plz explain d sol.......
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