If the logical memory of 8 X 1024 is mapped into 32 frames, then the number of bits for the logical address are____ ?
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    A log2(8X1024) = log2(8)+log2(1024) = 3+10 = 13



  • Warning: Illegal string offset 'name' in /home/prepdo6/gpl4you/discussquessub.php on line 681
    A there are 8 pages
    there are 1024 words per each page
    So log 8 =3 bits and log 1024 = 10 bits
    LA= 3+10 =13



  • Warning: Illegal string offset 'name' in /home/prepdo6/gpl4you/discussquessub.php on line 681
    A its ans is 13


    CpjJwWHV   how??plz explain
    14 years ago

    Smiley


  • Warning: Illegal string offset 'name' in /home/prepdo6/gpl4you/discussquessub.php on line 681
    A its ans must be 5 bits...1024/32 =32 (2^5)



  • Warning: Illegal string offset 'name' in /home/prepdo6/gpl4you/discussquessub.php on line 681
    A can u plz explain d sol.......


    CpjJwWHV   it may be 256 .....
    since logical address is divided into pages = main memory is divided into frames...
    14 years ago

    Smiley


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  • Warning: Illegal string offset 'name' in /home/prepdo6/gpl4you/discussquessub.php on line 682
    b 256

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