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There are five friends Amisha, Binaya, Celina, Daisy and Eshaan. Two of them play table tennis while the other three play different games, viz. football, cricket and chess. One table tennis player and the chess player stay on the same floor while the other three stay on floors 2, 4 and 5. Two of the players are industrialists while the other three belong to different occupations viz. teaching, medicine and engineering. The chess player is the oldest while one of the table tennis players, who plays at the national level, is the youngest. The other table tennis player who plays at the regional level is between the football player and the chess player in age. Daisy is a regional player and stays on floor 2. Binaya is an engineer while Amisha is the industrialist and plays tennis at the national level.
[1] Who stays on floor 4?
(A) Amisha
(B) Binaya
(C) Celina
(D) Eshaan[2] What does Eshaan play?
(A) Chess
(B) Football
(C) Cricket
(D) Table tennis at regional level[3] Age wise, who among the following lies between Daisy and Eshaan?
(A) Teacher
(B) Industrialist
(C) Engineer
(D) Doctor[4] Who all stay on floor 3?
(A) Amisha and Binaya
(B) Daisy and Eshaan
(C) Binaya and Daisy
(D) Celina and Daisy[5] What is the occupation of the chess player?
(A) Engineer
(B) Industrialist
(C) Doctor
(D) Teacherasked in JMET
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A biscuit company makes cream biscuits that have 5 cm diameter and 0.5 cm thickness. It markets these biscuits in cylindrical packets of 5, 10, and 20 pieces each. The gaps between biscuits as well as between the packing and the biscuits are negligible. The ends of each packet are sealed with cardboard caps that have the company's logo printed on them. In your calculations, use pie = 22/7.
[1] The total surface areas of the above three types of packets will have the following proportion:
(1) 1 : 2 : 2.5
(2) 1 : 2 : 3
(3) 1 : 1.5 : 2
(4) 1 : 1.5 : 2.5[2] The Company buys printed packing sheets made of paper each having 100 × 66 cm2 area. At full capacity, the company makes 3.5 lakhs biscuits per day. If it makes 10,000 packets each of the 5's, 10's and 20's, what is the minimum number of packing sheets required daily?
(1) 417
(2) 419
(3) 420
(4) 418
[3] The cost of each biscuit is Rs. 0.40, each packing sheet is Rs. 168, and that of each end-cap is Rs. 0.50. All other costs work out to Rs. 1 per packet, irrespective of the size of the packet. The maximum retail price of the 5's, 10's and 20's Packets are Rs. 8, 14, and 23 respectively. The profits per packet P5, P10 and P20, made by the company on the 5's, 10's and 20's packets respectively will be in the proportion:
(1) 1 : 2 : 3
(2) 1 : 1.5 : 2.5
(3) 1 : 1.75 : 2.875
(4) 1 : 2 : 4[4] Based on a study of its sales over the last three years, the company decides to produce only 5000 packets of 20's. The production capacity thus made available is used to produce additional 5's and 10's packets to meet the market demand. Let x1 and x2 respectively represent the additional numbers of 5's packets (in thousands), and 10's packets (in thousands). For every thousand of the additional 5's packets, the company has 15 distributors, and for every thousand of the additional 10's packets, it has 5 distributors. The company can utilize the services of a maximum of 75 distributors for these additional packets. Then the product-mix problem for producing the additional packets of 5's and 10's (in thousands) can be modelled using a Linear Programming Formulation. Which of the following statements about this model is incorrect?
(1) Maximize P5 × x1 + P10 × x2 can be the objective function
(2) 15x1 + 5x2 ≤ 75 is a constraint
(3) 5x1 + 10x2 = 100 is a constraint
(4) x1 and x2 ≥ 0, and integers[5] How many additional thousand packets of 5's and 10’s should the company produce to maximize its profits?
(1) x1 = 3; x2 = 7
(2) x1 = 2; x2 = 10
(3) x1 = 2; x2 = 9
(4) solution is infeasible[6] The 5’s, 10's and 20's biscuit packets are produced in lot sizes of 100 each. Three packets each of 5's, 10's and 20's are inspected at random. If even one biscuit is found broken in any of the three, the respective lot is rejected, the probability that 1 broken biscuit will be found in a 5's, 10's or 20's packet is estimated to be 0.10, 0.20 and 0.30 respectively. If a sample of three packets each of 5's, 10's and 20's is inspected, which probability distribution should we use to estimate the probability that all nine packets will be accepted?
(1) Normal (2) Binomial (3) Poisson (4) Hyper geometric
[7] What is the probability that all nine packets will be accepted'?
(1) 0.749 (2) 0.006 (3) 0.128 (4) 0.504asked in JMET
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