If number of occurrence of '3' is more than number of occurrence of '8' then replace row(2) by row(5) then column(3) by column(5). If it is less than occurrence of '8' then replace row(3) by row(5) then column(2) by column(4), then the element at position (4 x 3) is
A :
3
B :
8
C :
7
D :
9
Answer: A
Q. No. :
2
Question :
If we diagonally change the element(from top left to bottom right), by keeping '8' fixed(i.e does not change its position), then the element at position (2 x 3) is
A :
4
B :
8
C :
9
D :
3
Answer: C
Q. No. :
3
Question :
Replace row(2) by row(5) followed by column(2) by column(4), then the element at position (3 x 4) is
A :
3
B :
7
C :
9
D :
1
Answer: B
Q. No. :
4
Question :
Change all the rows with equal number of column (in increasing order), by keeping '9' fixed. Find the element at position (3 x 2).
A :
4
B :
3
C :
9
D :
7
Answer: D
Q. No. :
5
Question :
Replace all '4' by '1' and '1' by '2'. If {3(M(2,3))+2M(4,2)+M(3,5) } is odd replace row(2) by row(4), then find the position of element(2 x 5). If {3(M(2,3))+2M(4,2)+M(3,5) } is even replace column(2) by column(4), then find the position of element(4 x 4).
A :
4
B :
7
C :
6
D :
3
Answer: D
Solve the following question by using the matrix given below:- 9 10 11 12
5 13 17 19
4 8 12 16
7 2 3 5
Q. No. :
6
Question :
Change row(3) by col(3) and then column(3) by column(1) then the element at (4 x 3) is
Step 1.
Exchange the row(2) by col(2) a e c d
b f j n
i g k l
m h o p Step 2. Exchange the row(4) by col(4) a e c m
b f j h
i g k o
d n l p element at the position (4 x 3) is l
Q. No. :
12
Question :
In the above question change the row(3) by column(3), then the element at (3 x 2) is
Given Matrix: a b c d e f g h i j k l m n o p Change the row(3) by column(3) : a b i d e f j h c g k o m n l p Element at (3x2) is g
Q. No. :
13
Question :
Change all the rows by the column of same numbers, and doing the same by keeping the element d fixed for the next, then the element at position (3 x 3) is
The trace of an n-by-n square matrix is defined to be the sum of the elements on the main diagonal Trace = a + q + w + 4 Given, a = 1, q + w = 0 So Trace = 1 + 0 + 4 = 5
Q. No. :
17
Question :
If we diagonally change the elements by keeping a fixed then the element above r is?
det(M) is determinant value of the matrix M. Det(M) =
1
2
3
4
16
17
18
19
21
22
23
24
1
2
3
4
= 0
Q. No. :
20
Question :
If we change the column(1) by column(4) and then row(1) by row(3) then the element above 2 is
A :
v
B :
b
C :
q
D :
none of these
Answer: B
Five questions are based on the matrix given below:-
@ % # ! ?
) + ? * )
+ * ) > <
/ ) ? ( (
) - # @ =
Q. No. :
21
Question :
What is the element that is left to the element that is below the element in row four column 4.
A :
-
B :
)
C :
(
D :
#
Answer: D
Q. No. :
22
Question :
If all the rows and column are interchanged(one by one in increasing order) then what is the third element of row five.
A :
(
B :
>
C :
<
D :
*
Answer: C
Q. No. :
23
Question :
Replace column(5) by column(2) then row(2) by row(5) followed by column(1) by column(4) then the element at the position (5 x 4) is
A :
*
B :
)
C :
?
D :
(
Answer: B
Q. No. :
24
Question :
Let '*'= 1, '?'=2, '!'=3, '<'=9 and '('=7 If the sum of all the numbers is even then reverse the element (from top left to bottom right), if it is odd then reverse the element (from bottom left to top right). Find the element at the position (3 x 2).
A :
>
B :
?
C :
)
D :
*
Answer: B
Q. No. :
25
Question :
Replace row(2) by row(4), then column(3) by column(1). Find the element at position (4 x 3).
Four conditions:
4 Men 1 Woman
3 Men 2 Women
2 Men 3 Woman
1 Men 4 Woman
6C4 * 4C1 + 6C3 * 4C2 + 6C2 * 4C3 + 6C1 * 4C4 = 246
Q. No. :
2
Question :
Two solutions of 90% and 97% purity are mixed resulting in 21 litres of mixture of 94% purity. How much is the quantity of the first solution in the resulting mixture?
A :
15 litres
B :
12 litres
C :
9 litres
D :
6 litres
Answer: C
Q. No. :
3
Question :
A can do a work in 6 days and B in 8 days. With the help of a boy, the three complete the work in 3 days and get Rs 200. What is the boy's share, if the money is distributed in the ratio of work done?
A can do a work in 6 days and B in 8 days. So in 1 day A do 1/6 work and in 1 day B do 1/8 work
In 3 days work done by A = 3/6=1/2 In 3 days work done by A = 3/8
So work done by boy in 3 days = 1-(1/2+3/8) = 1-7/8 = 1/8 So boy's share = 200 * 1/8 = 25 Rs
Q. No. :
4
Question :
8 chairs are numbered from 1 to 8. Two women first choose two chairs from those marked 1 to 4 and 3 men selects 3 chairs from the remaining. Find the number of possible arrangements.
A :
288
B :
6720
C :
720
D :
1440
Answer: D
Q. No. :
5
Question :
A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is: